Current through Register Vol. 46, No. 12, March 20, 2024
(a)
Determine the number of "S" intervals in a sample class.
(1) For survey units exclusive of those in
the special assessing unit of Nassau County determine the initial number of "S"
intervals in a sample class from Table 1 below.
(i) If the number of parcels in the sample
class is less than 16 parcels, the initial number of intervals equals the
number of intervals indicated in the table.
(ii) If the number of parcels in the sample
class is greater than 15 parcels, the initial number of intervals is equal to
the number of intervals indicated in the table minus one.
TABLE 1
Number of parcels in sample
class |
Number of
intervals |
Minimum interval
sample size |
less than 7 |
1 |
Number of parcels |
7 to 15 |
2 |
3 |
16 to 79 |
3 |
3 |
80 to 499 |
4 |
3 |
500 to 999 |
4 |
4 |
1,000 to 3,999 |
5 |
4 |
4,000 to 9,999 |
6 |
4 |
10,000 to 19,999 |
7 |
4 |
20,000 to 29,999 |
8 |
4 |
30,000 to 39,999 |
9 |
4 |
equal to or greater than 40,000 |
10 |
4 |
(2) For the special assessing unit of Nassau
County, determine the initial number of "S" intervals in a sample class from
Table 2 below.
(i) If the number of parcels in
the sample class is less than 20, the initial number of intervals equals the
number of intervals in the table.
(ii) If the number of parcels in the sample
class is greater than 19, the initial number of intervals equals the number of
intervals indicated in the table minus one.
TABLE 2
Number of parcels in sample
class |
Number of
intervals |
Minimum interval
sample size |
less than 13 |
1 |
Number of parcels |
13 to 19 |
2 |
6 |
20 to 79 |
3 |
4 |
80 to 499 |
4 |
4 |
500 to 999 |
4 |
5 |
1,000 to 3,999 |
5 |
4 |
4,000 to 9,999 |
6 |
4 |
10,000 to 19,999 |
7 |
4 |
20,000 to 29,999 |
8 |
4 |
30,000 to 39,999 |
9 |
4 |
equal to or greater than 40,000 |
10 |
4 |
(b) Determine the boundaries and contents of
"S" intervals.
(1) Sum the parcel assessed
values in the sample class from high to low, and test the sum after each parcel
is added.
(2) At each step in the
process, test the cumulative assessed value of the interval being constructed
against the result of the sample class total assessed value, minus the
cumulative assessed value of previously completed intervals, divided by the
number of intervals left to be completed.
(3) When the test indicates that, including
the latest parcel added, the cumulative assessed value for the interval exceeds
the test amount, the latest parcel is determined to be included in the
interval, and the interval being processed is complete.
(4) When an interval is complete, the
interval total assessed value is subtracted from the sample class test amount
remaining to be assigned, and the count of intervals remaining to be
constructed is reduced by one.
(5)
This procedure continues until all parcels in the sample class have been
assigned to a value interval.
(6)
For identification purposes, the value interval which contains the parcel with
the lowest assessed value is numbered "001." Subsequent intervals are
identified from high to low by adding one to the previous interval identifying
number.
(c) Determine
boundaries and contents of subintervals.
(1)
Examine the first value interval (S001) and determine the number of parcels
that it contains.
(i) If the interval contains
less than 15 parcels, or all the parcels in the original interval have the same
assessed value, the boundaries and contents of the interval remain
unchanged.
(ii) If the interval
contains 15 or more parcels with different assessed values, create two
subintervals by comparing the assessed values of the parcels in the original
interval to the mean assessed value of the original interval and assigning
parcels, highest assessed value to lowest, to the higher subinterval until an
assessed value not greater than the mean assessed value is found.
(iii) The first parcel found with an assessed
value not greater than the mean assessed value of the original interval, and
all remaining parcels from the original interval, are assigned to the lower
subinterval.
(2) For
identification purposes, the subinterval which contains the parcel with the
lowest assessed value is numbered "001." The second subinterval is numbered
"002." Subsequent intervals are identified from low to high by adding one to
the previous interval identifying number.
(d) Allocate class tentative sample size to
"S" intervals.
(1) The class tentative sample
size, rounded to the nearest integer, is divided by the number of intervals,
resulting in an integer and a remainder. Interval sample sizes are then set,
from the lowest value to the highest, equal to the integer plus one for the
number of intervals equal to the remainder, and equal to the integer for any
additional intervals.
(2) Compare
the interval sample sizes from paragraph (1) of this subdivision to the minimum
interval sample sizes shown in subdivision (a) of this section; the larger
sample size is the interval sample size.
(3) A sample class in the special assessing
unit of Nassau County which has greater than 19 parcels and two intervals has a
minimum interval sample size of six. A sample class in the special assessing
unit of Nassau County which has greater than 19 parcels and three intervals has
a minimum interval sample size of four.
(4) Where the interval sample size would be
greater than the number of parcels in the interval, the interval sample size is
equal to the number of parcels.
(5)
The sum of the interval sample sizes is the sample class sample size.
(6) Sample class sample size cannot exceed
the number of parcels in the class.
(e) Randomly select the sample parcels and
alternates for each "S" interval.
(f) Assign to each large unit exactly one "T"
interval and select the large unit as the sample parcel for that
interval.